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A simple proof for $\sum_{k=1}^\infty {1 \over 2k+1} = {1 \over 2}$

It is easy to give a proof for $\sum_{k=1}^\infty {1 \over 2k+1} = {1 \over 2}$ in the usual way, using that ${1 \over 2k+1} = {1 \over 2}\cdot {1 \over 2k}$, it is a very well known proof.
Well, I was thinking, let’s see if we could get to the same conclusion using that fact that
$$(2n-1)^2 \ge 2n+1 \mbox{ for any natural number }n \ge
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