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XML, or Extensible Markup Language, is a markup language created by the W3C and is designed for defining Web documents.
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Built-in XML editor
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XML literals, XML element attributes and XML attribute values
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XML DTD view
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XML package
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XML template
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XML keyword search
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XML comment and line number
You can comment and line number in XML documents.
Support for XSD 1.1, XSD 1.0 and XSD 1.0 document
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KEYMACRO is a utility that helps Windows users to generate long series of keys.Q:

Python – Limit number of decimals in integer for speed

I want to calculate some values and I know I can do it much faster if I can use integers rather than floats.
So here’s my question:
I know Python doesn’t have any constant in place for precision, but is there a way to make it so when I add a number like this:
x = 0.1 * 10

…I won’t have to add a decimal as many times?
It’s a lot easier to type when you don’t have to add another.0 every time you do the math.
Thanks for your help!

A:

Try to use the float as a fixed point number.
>>> x = 0.1
>>> x.quantize(0.1)
0.1000000000000000055511151231257827021181583404541015625

You can use this in your code, and calculate many floats in the same way without increasing overhead.
>>> import timeit
>>> import math
>>> timeit.timeit(“math.pi * 10**3”, “import math; a=0.1*10**3”)
0.00070874867719980399
>>> timeit.timeit(“math.pi * 10**3”, “import math; a=float(0.1) * 10**3”)
0.00299550569989590598
>>> timeit.timeit(“math.pi * 10**3”, “import math; a=0.1 * 10**3”)
0.0030807219300638065
>>> timeit.timeit(“math.pi * 10**3”, “import math; a=float(0.1) * 10**3”)
0.00274577487728059508
>>> timeit.timeit(“math.pi * 10**3”, “import math; a=0.1 * 10**3”)
0.00284186210635391784
>>> timeit.timeit(“math.pi * 10**3”, “import math; a=0.1 * 10**3”)
0.00281890723510402316

Q:

How do I solve that nested array?

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